A gardener planted some seedlings at equal distances apart along a straight road the 3rd seedling and the 5th seedling were 9/10 m apart . The 2nd seedling and the last seedling were 6 3/4 m apart . How many seedlings did he plant
Answers
Answer:
17 seedlings
Step-by-step explanation:
Given;
The seedlings are at an equal distance in a straight line.
Distance between 3rd seedling and 5th seedling = 9/10 m
So, distance between 3rd seedling and 4th seedling = 9/10 ÷ 2 = 9/20 m
So, the distance between two seedlings in a line = 9/20 m
The given distance between 2nd seedling and the last seedling = 6 3/4 m = 27/4 m
Starting from 2nd seedling:
9/20 * x = 27/4
Where x = the number of times 9/20 to reach the last seedling.
x = 15
So, from 2nd seedling we need to move 15 positions to get a distances of 27/4.
Moving from 2 to 17, we get 17 as the last seedling.
So, the total number of seedlings = 17 seedlings.
Answer:
17 seedings he planted
Step-by-step explanation:
A gardener planted some seedlings at equal distances apart along a straight road the 3rd seedling and the 5th seedling were 9/10 m apart . The 2nd seedling and the last seedling were 6 3/4 m apart . How many seedlings did he plant
Let say n plant are seeded
initial Positiona of first seed = a
Then they are at equal distance = d
3rd seeding Position = a + 2d
5th seeding Position = a + 4d
3rd seedling and the 5th seedling were 9/10 m apart
=> a + 4d - ( a + 2d) = 2d = 9/10
=> d = 9/20 m
2nd seedling = a + d
nth seeding (Last seed) = a + (n-1)d
The 2nd seedling and the last seedling were 6 3/4 m apart
=> a + (n-1)d - (a + d) = (n-2)d = 27/4
=> (n-2)(9/20) = 27/4
=> n-2 = 15
=> n = 17
17 seedings he planted