Question

A gardner waters plant by a pipe of cross section 1mm2 the water come out at the rate of 100cc/s the reactionary forces

Answer 1

Answer:

The reactionary force is 0.1274 N

Explanation:

Diameter of pipe = 1 mm;

Radius=Diameter/2;

R=1/2=0.5 mm;

Convert mm to m;

1 mm=0.001 m so R=0.005 m;

Area of cross-section of the pipe is, A = πr2

Density of water is, d = 1000 kg/m3

Volume of water coming out per sec is = 10 cm3/s = 10-5 m3/s

Mass of water coming out per sec is,

dm/dt = density × volume/sec

= (1000)(10-5) kg/s = 10-2 kg/s

dm/dt = 10-2 kg/s

Now,

Volume/sec = Area × velocity

A = πr2

= 3.14 x (0.00052)

=> 10-5 = (3.14) × (0.00052) × v

=> v = 12.74 m/s

Now, force = change in momentum/sec

=> F = d(mv)/dt

=> F = v(dm/dt) [velocity, ‘v’ is constant]

=> F = (12.74)(10-2)

=> F = 0.1274 N

Answer 2

Answer:10N

Explanation:

Solved in image below