a gardener push a roller through a distance of 20 m if we apply a force of 20 kg weight in the direction of inclined plane at 60 degree find the work done
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Component of force in direction of displacement = F cosΘ
∴Component of force along displacement
=20×cos(60)×9.8N [as 1 kgwt =9.8N]
=98 N
Work done = Displacement × Component of force along displacement
∴Work done = 98N ×20m
= 1960 J
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