A gardener was asked to plant equal number of plants in rows. He had completed 6, 8, 10 and 12 plants in each row but every time 5 plants were left. When he planted 13 plants in a row, no plant was left. Will the minimum number of plants be?
(a) 245 (b) 125
(c) 485 (d) 845
guys tell me how to solve it...
Answers
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Solution :-
L.C.M. of 6, 8, 10 and 12
6 = 2*3
8 = 2*2*2
10 = 2*5
12 = 2*2*3
L.C.M. of 6, 8, 10 and 12 = 2*2*2*3*5 = 120
When equal number of trees are planted in rows of 6, 8, 10 or 12, five trees are left unplanted.
Hence, number of trees will be (120x + 5), which must be divided by 13 as per the given condition in the question.
By hit and trial method =
(120x + 5)/13 will be satisfied for x = 7
(120*7) + 5
So, total number of trees = 840 + 5 = 845
845 is exactly divisible by 13.
D is the answer...
L.C.M. of 6, 8, 10 and 12
6 = 2*3
8 = 2*2*2
10 = 2*5
12 = 2*2*3
L.C.M. of 6, 8, 10 and 12 = 2*2*2*3*5 = 120
When equal number of trees are planted in rows of 6, 8, 10 or 12, five trees are left unplanted.
Hence, number of trees will be (120x + 5), which must be divided by 13 as per the given condition in the question.
By hit and trial method =
(120x + 5)/13 will be satisfied for x = 7
(120*7) + 5
So, total number of trees = 840 + 5 = 845
845 is exactly divisible by 13.
D is the answer...
abcdxyz4:
thanks bro
mark it as brainliast
ok
(120x + 5)/13 will be satisfied by x=7....... i didn't understand how
please tell me bro
you should try x= 1,2,3......,7 to get number divisible by 13
ok. thanks bro
bro i asked one another question...
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