Question

A garrison of 120 man has provision for 30 days. at the end of five days, five more men joined them. how many days they can sustain on the remaining provision?

Answer 1

Food last for 120 men for 30 days
Reinforcement=5man
Total number of men=120+5=125
Food last for 1 man =120×30
Food last for 125 men=120×30÷125
= 3600 ÷ 125
=28.8 days
Therfore the food will last for 28 days 8 hrs

Answer 2

Given:

A garrison of 120 men has provision for 30 days. At the end of 5 days, five more man joined them.

To Find:

How many days can they sustain on the remaining provision

Solution:

We are given that A garrison of 120 men has provision for 30 days.

We are also given that At the end of 5 days, five more man joined them.

We are supposed to find How many days can they sustain on the remaining provision

Total provision = $120 \times 30 = 3600$units

120 men in 5 days will take = $120 \times 5 = 600$ units of provision

Remaining provision = 3600–600 = 3000 units

5 more men joined and now there are total 125 men

1 day provision requirement for 125 men = 125 units

Days for which they can sustain on remaining provision =$\frac{3000}{125} = 24$days

Hence they sustain for 24 days✍