a Garrison of 120 member has provision for 30 days at the end of 5 days 5 more member join them how many days can be 16 for remaining provision please help for this answer
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We know that no. of days is inversely propotional to the provision for men.
So for 120 men the provision would last for 30days. (given)
Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days.
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days
A.t.q 120*30 = 120*5+125*x
(120*30) - (120*5)= 125x
120(30-5)=125x
120 * 25 = 125x
120 = 5x
x=120/5
x= 24
So for 120 men the provision would last for 30days. (given)
Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days.
Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days
A.t.q 120*30 = 120*5+125*x
(120*30) - (120*5)= 125x
120(30-5)=125x
120 * 25 = 125x
120 = 5x
x=120/5
x= 24
kanchansharma1005:
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hi , Kanchan hope this will help u
A Garrison of 120 member has provision for 30 days
at the end of 5 days 5 more member joined
after 5 days,
days left for the food to last =30-5 =25 days
total soldiers now =120+5 =125
Let the nos of days be x
as it varies inversely that means more the member less days food will last
⇒so 120*25=125*x
⇒x= 120*25/125
⇒x=24
therefore required number of days=24
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