Question

A garrison of 120 men has provisions for 30 days. Suppose only 100 men were there, how many days can they sustain on the provision?​

Answer 1

Step-by-step explanation:

Let after the joining of 5 men (after 5 days), It took x days to sustain on the remaining provision then,

According to the question-

120×30=120×5+125×x

(120×30)−(120×5)=125x

120(30−5)=125x

120×25=125x

120=5x

x=24 days

Hence, this is the required answer.