Question

A gas A having molecular weight 4 diffuses thrice as fast as the gas B at a given T. The molecular weight of gas B is :​

Answer 1

Answer:

The rate of diffusion is inversely proportional to the molar mass.

$r = 1 \div \sqrt{m}$

Where,

r= rate of diffusion

M= molar mass

r and r' are the rate of diffusion of gas 'A' and gas 'B' respectively.

M and M' are the molar mass of gas 'A' and gas 'B' respectively.

[tex]r/r'=sqrtM'/M[/tex]

[tex]3r'/r'=sqrtM'/4[/tex]

[tex]3=sqrtM'/4[/tex]

[tex](3)^2=M'/4[/tex]

[tex]9=M'/4[/tex]

[tex]M'=36[/tex]

The molecular weight of gas B(M') is 36

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