Question

A gas absorbs 250 J of heat and expands from 1
litre to 10 litre at constant temperature against
external pressure of 0.5 atm. The values of q, w and ΔE respectively ​

Answer 1

Explanation:

Here work done is -p∆v=0.5×9=-4.5

Temperature is constant so Change in internal energy is zero

Hence heat absorbed is work done ......i.e. +4.5