A gas ansorbs a photon of 355n.m and emits two wave lengths if there wave length of 1st one is 680n.m,caluclate the wave length of 2nd
Answers
Answered by
1
Answer:
Absorbed energy = Emitted energy
λ
hc
=
λ
1
hc
+
λ
2
hc
λ
1
=
λ
1
1
+
λ
2
1
355
1
=
680
1
+
λ
2
1
λ
2
=743nm.
Answered by
1
Answer:
743nm
Explanation:
Absorbed energy = Emitted energy
λhh= λ 1
hh+ λ 2hhcλ1
= λ 11+ λ 21
3551
=6801+ λ 21
λ 2 =743nm.
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