Chemistry, asked by galaiahvalluri2006, 5 hours ago

A gas ansorbs a photon of 355n.m and emits two wave lengths if there wave length of 1st one is 680n.m,caluclate the wave length of 2nd​

Answers

Answered by s2367deepansh00252
1

Answer:

Absorbed energy = Emitted energy

λ

hc

=

λ

1

hc

+

λ

2

hc

λ

1

=

λ

1

1

+

λ

2

1

355

1

=

680

1

+

λ

2

1

λ

2

=743nm.

Answered by lionsgaming010
1

Answer:

743nm

Explanation:

Absorbed energy = Emitted energy

λhh= λ 1

hh+ λ 2hhcλ1

= λ 11+ λ 21

3551

=6801+ λ 21

λ 2 =743nm.

Similar questions