which of √2 and 2 isa zero of polynomial p(x)=x square-2x
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Answered by
0
Answer:
it's easy to explain
Step-by-step explanation:
Given polynomial p(x)=2x2−3x+7a is zero polynomial if x is 2
Replace x by 2 we get
∴2(2)2−3(2)+7a=0
⇒2×4−3×2+7a=0
⇒8−6+7a=0
⇒2+7a=0
Add -2 both sides we get
2+7a−2=0−2
⇒7a=−2
Divided by 7 both side we get
a=−72
So a=−72
Answered by
0
p(x)=x²-2x
subtitute x=√2
»(√2)²-(2×√2)
»2-2√2≠0
substitute x=2
»(2)²-(2×2)
»4-4=0
2 is the zero of the polynomial x²-2x
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