Question

A gas at a pressure 5atm is heated from 0°C to 546°C and simultaneously compressed to 1/3rd of its original value. Hence final pressure.
*10atm
*45atm
*30atm
*5atm

Answer 1

Answer : The correct option is, 45 atm

Solution :

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 5 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 3x L

$V_2$ = final volume of gas = x L

$T_1$ = initial temperature of gas = $0^oC=273+0=273K$

$T_2$ = final temperature of gas = $546^oC=273+546=819K$

Now put all the given values in the above formula, we get the final pressure of the gas.

$\frac{5\times 3x}{273}=\frac{P_2\times x}{819}$

$P_2=45atm$

Therefore, the final pressure of the gas is, 45 atm.

Answer 2

Answer:

Explanation:

The combined gas equation is,

P1V1/T1 = P2V2/T2

where,

= initial pressure of gas = 5 atm

= final pressure of gas = ?

= initial volume of gas = 3x L

= final volume of gas = x L

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above formula, we get the final pressure of the gas.

Therefore, the final pressure of the gas is, 45 atm.