Question

a gas at a pressure of 5 atm is heated from 0°c to 546°c and simultaneously compressed to 1/3 of its original volume.Hence final pressure is

Answer 1

:P1 = 5 atm
T1 = 273 K ;
T2 = (273 + 546) K= 819 K
V1 = V1
V2 = V1/3
Combining the gas laws, we obtain
P1V1÷T1=P2V2÷T2
or P2=P1V1×T2÷V2×T2
=>now substituting value
=>5×V1×819÷V1/3×273
=>5×819×3÷273 ( V1 cancelout with V1)
=>45atm

Hope it will help you!!!

Answer 2

Given that,

Initial pressure = 5 atm

Initial temperature = 0°C = 0+273 = 273 K

Final temperature = 546°C = 546+273 = 819 K

Final volume = 3x

Initial volume = x

We need to calculate the final pressure

Using combined gas equation

$\dfrac{P_{1}V_{1}}{T_{1}}=\dfrac{P_{2}V_{2}}{T_{2}}$

Where, P₁ = initial pressure

V₁ = initial volume

V₂ = final volume

T₁ = initial temperature

T₂ = final temperature

Put the value into the formula

$\dfrac{5\times 3x}{273}=\dfrac{P_{2}\times x}{819}$

$819\times15x=P_{2}\times273x$

$P_{2}=\dfrac{819\times15}{273}$

$P_{2}=45\ atm$

Hence, The final pressure is 45 atm