Question

If x+y=12,xy=32 find x^2+y^2

Answer 1

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Here's your answer

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If x+y = 12 & xy = 32 then the value of x^2+y^2 is----

${x}^{2} + {y}^{2} \\ = (x + y) - 2xy \\ = 12 - 2 \times 32 \\ = 12 - 64 \\ = - 52$

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Answer 2

1 x+y=12
2 xy=32
find 3 x^2+y^2
X=8
Y=4
8+4=12
8*4=32
8*8+4*4=80