Question

A gas cylinder can withstand a pressure
of 16 atm. At what temperature cylinder
will explode if the pressure of the gas in
12 atm at 25°C in the cylinder.
А
500 K
B
250 K
С
350 K
D
397.3 K​

Answer 1

Answer:

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Explanation:

P

1

=12bar,T

1

=27+273=300K

P

2

=14.9 bar,T

2

=?

Applying pressure temperature law,

P

2

P

1

=

T

2

T

1

or T

2

=

P

1

T

1

×P

2

Substituting the values in the above equation,

T

2

=

12

300×14.9

=372.5K

Temperature in

0

C=372.5−273=99.5

∘

C

Hence the cylinder will explode at a temperature 99.5

∘

C