A gas cylinder having a capacity of 20 liters contains a gas at 100 atoms. how many flasks of 200cm3 capacity can be filled from it at 1 atoms. pressure if the temperature remains constant ?
Answers
Answered by
8
Hi friend,
===============
Let n numbers of flasks required .
20 L = 20,000 cm^3
Apply boyel's Law,
P1V1=P2V2
P1= 100 amt
V1 = 20,000 cm^3
P2 = 1 amt
V2 = n*200cm^3
therefore, P1V1=P2V2
100*20,000 = 1*n*200
Hence, N = 10,000
....i hope it helps you
====================
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===============
Let n numbers of flasks required .
20 L = 20,000 cm^3
Apply boyel's Law,
P1V1=P2V2
P1= 100 amt
V1 = 20,000 cm^3
P2 = 1 amt
V2 = n*200cm^3
therefore, P1V1=P2V2
100*20,000 = 1*n*200
Hence, N = 10,000
....i hope it helps you
====================
mark me as a brainlist.
enormous010:
please mark me as a brainlist.
Answered by
2
Answer:
Explanation:
Hi friend,
===============
Let n numbers of flasks required .
20 L = 20,000 cm^3
Apply boyel's Law,
P1V1=P2V2
P1= 100 amt
V1 = 20,000 cm^3
P2 = 1 amt
V2 = n*200cm^3
therefore, P1V1=P2V2
100*20,000 = 1*n*200
Hence, N = 10,000
....i hope it helps you
====================
mark me as a brainlist.
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