A gas cylinder having a capacity of 20 litres contains a gas at 100atoms. How many flasks of 200 cm^3 capacity can be filled from in at 1 atoms pressure remains constant?
Answers
Answered by
6
For a given quantity of a gas at constant temperature,
P x V = a constant value (See 'Boyle's Law')
So if the initial and final conditions of pressure and volume are given by P1, V1, P2 and V2
Then P1 x V1 = P2 x V2
So, 100atm x 20000cm^3 = 1atm x V2cm^3
So V2 = 10^2 x 2 x10^4 / 1 = 2 x 10^6 cm^3
Since each flask has a capacity of 200cm^3
Number of flasks filled = 2 x 10^6 / 2 x 10^2 = 10^4
So, 10000 flasks can be filled.
P x V = a constant value (See 'Boyle's Law')
So if the initial and final conditions of pressure and volume are given by P1, V1, P2 and V2
Then P1 x V1 = P2 x V2
So, 100atm x 20000cm^3 = 1atm x V2cm^3
So V2 = 10^2 x 2 x10^4 / 1 = 2 x 10^6 cm^3
Since each flask has a capacity of 200cm^3
Number of flasks filled = 2 x 10^6 / 2 x 10^2 = 10^4
So, 10000 flasks can be filled.
Answered by
3
Question:
A cylinder of 20 litres capacity contains a gas at 100 atmospheric pressure. How many flasks of 200 cm³ capacity can be filled from it at 1 atmosphere pressure, temperature remaining constant?
Answer:
Given:
V1=20L=20000cm³
P1=100atm
V2=?
P2=1
According to Boyles' Law,
P1V1=P2V2
Solution:
100 × 20000 = 1 × V2
2000000 = V2
Also asked that,
how many flasks of 200 cm³ capacity can be filled from it at 1 atmospheric pressure and temperature remain constant.
Therefore,
According to Question:
2000000cm³ ÷ 200cm³
=10000 flasks Ans
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