A gas diffuese 4times as quickly as oxygen the molecular weight of a gas is
Answers
Explanation:
To solve the given problem, Graham's law related to rate of diffusion is needed. The “Graham's law" states that the "rate of diffusion" or "of effusion" of a "gas" is "inversely proportional" to the "square root" of its "molecular weight”. The "formula" can be written as:
Where:
Rate 1 - "Rate of diffusion" of 1st gas.
Rate 2 - "Rate of diffusion" of 2nd gas.
- Molar mass of 1st gas
- Molar mass of 2nd gas
Given:
Gas 1 - Unknown gas
Gas 2 - Oxygen gas
Molecular mass () of oxygen is 32
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As the gas 1 diffuses 4 times faster than oxygen, the
Substituting the given value in Graham's equation:
Squaring both sides we get:
In the "periodic table", the gas with molecular mass as 2 is hydrogen. Thus, it can be inferred that hydrogen diffuses "four times faster" than oxygen and the molecular mass of the gas is 2 gram/mol."