a gas having temperature 0°C is heated so that its pressure and volume are doubled. what will be the final temperature
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no of mole constant
question ask
volume is doubled
let initial volume =v
then final volume=2v
also let initial pressure =p
then final pressure=2p
now use
piVi/Ti=pfVf/Tf
pv/(273K)=(2p)(2v)/Tf
Tf=273 x 4=1092K
hence final temperature =1092K=819 C
question ask
volume is doubled
let initial volume =v
then final volume=2v
also let initial pressure =p
then final pressure=2p
now use
piVi/Ti=pfVf/Tf
pv/(273K)=(2p)(2v)/Tf
Tf=273 x 4=1092K
hence final temperature =1092K=819 C
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Answered by
0
let the pressure be p
and volume be v
New pressure = 2p
New volume = 2v
Temperature = 0 C = 273K
now
formula
p^2 x v/t = p1^2 x v1/t
p^2 x v/273 = 2p^2 x 2v /t1
t1= 4 x 273 = 1092K
final temperature= 1092-273= 819 C
and volume be v
New pressure = 2p
New volume = 2v
Temperature = 0 C = 273K
now
formula
p^2 x v/t = p1^2 x v1/t
p^2 x v/273 = 2p^2 x 2v /t1
t1= 4 x 273 = 1092K
final temperature= 1092-273= 819 C
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