Question

a gas is collected and found to fill 2.85 L at 25.0 °C . what will be it' volume by standard temperature.​

Answer 1

Explanation:

PV=nRT

v1/t1 = v2/t2

2.85L /25.0⁰c = v2/0⁰c

2.85L /298.15k = v2/273.15k

0.0095584=v2/273.25k

therefore, v2= 2.6L

Answer 2

Answer:

The volume of the gas will be equal to 2.61 L at standard temperature.

Explanation:

We have given the initial volume of the gas, V₁ = 2.85L

The initial temperature of the gas, T₁ = 25°C = 25 + 273 = 298K

Consider that the final volume of the gas is V₂ at standard temperature.

The final temperature of the gas, T₂  = 0°C = 273K

According to Charles law, for a given mass of a gas at constant pressure, the volume of gas directly proportional to its temperature.  

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

$V_2=\frac{V_1T_2}{T_1}$

Substitute the value of temperatures and volume in the above formula:

$V_2=\frac{(2.85)(273)}{298}$

V₂ = 2.61 L

Therefore, the final volume of the gas is equal to 2.61 L.

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