A gas is found to contain 2.34g of nitrogens and 5.34g of oxygens simplest formulae of the compound is
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2.34/14= N = 0.167
5.34/16 = O = 0.333
divide moles by least amount of moles
N = 0.167/.167 = 1
O = 0.333/.167 = 2
this way it can be found by emperical formula.
formula will be NO2
5.34/16 = O = 0.333
divide moles by least amount of moles
N = 0.167/.167 = 1
O = 0.333/.167 = 2
this way it can be found by emperical formula.
formula will be NO2
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