Question

A gun weighing 10kg fires a bullet of 30 g with a velocity of 330m/s with what velocity does the gun recoil what is the combined momentum of the gun and bullet before firing and after firing

Answer 1

Momentum of the bullet equals the momentum of the gun.

Momentum equals to :

Mass × Velocity

We substitute into the formulae and get :

0.03 × 330 = 10 × V

9.9 = 10V

V = 0.99 m/s

Momentum before firing is zero since both the gun and the bullet are at rest and their velocities are zero.

Momentum after firing is equal to momentum of the gun plus the momentum of the bullet which are equal and opposite.

This is therefore :

330 × 0.03 × 2 = 19.8Kgm/s

Answer 2

Explanation:

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