Question

A gas is present of 2 atm. What should
be the increase
in pressure so that
the volume
of
the
gas
be decreased
to 1/4th of the initial value o if the
temperature is maintained constant.
​

Answer 1

Answer:-

Given:

Initial Pressure of the gas (P1) = 2 atm.

Let the initial Volume(V1) be "V".

The Volume becomes 1/4 of its initial if the pressure is increased.

→ Final Volume (V2) = 1/4 * V = V/4

We know that,

Boyle's law of gases states that at constant temperature the pressure. of a gas is inversely proportional to it's Volume.

$\sf \implies \large{P \: \: \alpha \: \: \dfrac{1}{V} }$

→ PV = k (Constant)

→ P1V1 = P2V2

→ (2) * (V) = P2 * (V/4)

→ 2V * 4/V = P2

→ 8 = P2

→ P2 = 8 atm

Hence, the Volume becomes 1/4th of itself when the pressure is increased to 8 atm.