Question

A gas mixture contains 0.70 moles of nitrogen gas, 0.20 moles of hydrogen gas, and 0.10 moles of methane (CH4). What is the partial pressure of nitrogen?

Answer 1

If the total pressure of the mixture is 1.00 atm, the partial pressure of nitrogen is 0.70 atm.

The partial pressure

P

i

of a gas

i

is equal to its mole fraction

x

i

times the total pressure

P

i

of the mixture.

P

i

=

x

i

P

tot

and

x

i

=

n

i

n

tot

.

n

tot

=

n

N₂

+

n

H₂

+

n

CH₄

= (0.70 + 0.20 + 0.10) mol = 1.00 mol

x

N₂

=

0.70 mol

1.00 mol

= 0.70

P

N₂

=

x

N₂

P

tot

= 0.70 × 1.00 atm = 0.70 atm

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Answer 2

Explanation:

Ernest Z. If the total pressure of the mixture is 1.00 atm, the partial pressure of nitrogen is 0.70 atm.