Question

A gas occupied a volume of 250 \mathrm{ml}250ml at 700 \mathrm{mm} \mathrm{H} g700mmHg pressure and 250^{\circ} \mathrm{C}250 ∘
C. What additional pressure is required to reduce the gas volume to its 4 / 54/5 th value at the same temperature?

Answer 1

Answer:-

Given:

V1 = 250 ml.

P1 = 700 mm Hg.

V2 = V1(4/5) => 250*4/5

→ V2 = 200 ml.

We know that,

Boyle's law of gases states that at constant temperature the volume of the gas is inversely proportional to its Pressure.

$→ P \: \alpha \: \frac{1}{V}$

(Or)

P*V = K (Constant)

(or)

P1*V1 = P2*V2

→ (700)(250) = P2 * (200)

→ P2 = (700)(250)/200

→ P2 = 875 mm Hg.

Hence, the Pressure to be applied is 875 mm Hg.