A gas occupies 100.0 mL at 50°C and I atm pressure. The gas is cooled at constant pressure so that
volume is reduced to 50.0 mL. What is the final temperature.
(a)-111.5°C (b) 111.5°C (c) 111.5K (d) 384 K
Answers
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Explanation:
as pressure is constant
∆V = 0
V1/T1 = V2/T2
100/323 = 50 / T2
T2 = 323×50/100
T2 = 11.5K
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