a gas occupies 1000cm3 under 760mm of Hg pressure . find under what pressure the gas will occupy 600 cm3 keeping temperature constant
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Answered by
1
we know that for an ideal gas
pv=nrt
and hence
v=nrt/p
in the question it is given that the same gas is kept afterwards at a lower pressure and hence the no. of moles is same
so we know that the value of n,r,t are same (r is gas constant)
so
v 1/p
we also knoe that the final volume of gas is 75% of initial volume
=850*75/100 ml
so
volume initially(L)/volume final(L) =pressure final(atm) /pressure innitially(atm)
so
(850/1000) / (850*75/(100*1000))= (760/760) /
so
=0.75 atm
which equals 570mm of hg
i hope this helps if so plz approve this ans
pv=nrt
and hence
v=nrt/p
in the question it is given that the same gas is kept afterwards at a lower pressure and hence the no. of moles is same
so we know that the value of n,r,t are same (r is gas constant)
so
v 1/p
we also knoe that the final volume of gas is 75% of initial volume
=850*75/100 ml
so
volume initially(L)/volume final(L) =pressure final(atm) /pressure innitially(atm)
so
(850/1000) / (850*75/(100*1000))= (760/760) /
so
=0.75 atm
which equals 570mm of hg
i hope this helps if so plz approve this ans
purohitkumar:
Can u do it , according to boyles law because we have to do it in boyles law
Answered by
1
Bonjour!!!!
Here's the answer....
Mark brainliest if it helps....
Here's the answer....
Mark brainliest if it helps....
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