Question

A gas occupies a volume of 300cm^3 under a pressure of 350mm of Hg. Find under what pressure of the gas, it occupies a volume of 380cm^3. The temperature during the reaction remains constant.​

Answer 1

Answer:

Here, V

1

=300cm

3

, T=27

∘

C=300K, P

1

=620mm

T

2

=47

∘

C=320K, P

2

=640mm

From Ideal gas equation,

T

1

P

1

V

1

=

T

2

P

2

V

2

⇒

300

620×300

=

320

640×V

2

V

2

=

640×300

620×300×320

=310 cm

3

.

Answer 2

Given:

The initial volume of the gas = 300 $cm^3$

The initial pressure of the gas = 350mm of Hg

The changed volume of the gas = 380 $cm^3$

To find:

The pressure for the changed volume.

Solution:

It is given that the temperature remains constant for the whole process therefore this is an example of an isothermal process.

Now for an isothermal process, we know that

PV = constant

or

P1V1 = P2V2

Now it is given

P1 = 350mm of Hg

V1 = 300 $cm^3$

V2 = 380 $cm^3$

using these values we will get the value for P2

P2 = P1V1/V2

P2 = 350 x 300 / 380

P2 = 276.31 mm of Hg

Therefore at a pressure of 276.31 mm of Hg the gas will occupy the volume of 380$cm^3$.