Question

A gas occupy a volume of 2.5 litre at 9 into 10 to the power 5 newton per square calculate the additional pressure required to decrease the volume of the gas 21.5 leaving the temperature pressure

Answer 1

Hey

here's your answer

Given

P₁ = 9×10⁵ N m -²

P₂ = ?

V₁ = 2.5 L

V₂ = 1.0 l

According to boyle's law,

P₁V₁ = P₂V₂

9×10⁵ N m-2 × 2.5 L = P₂ × 1.0 L

P₂ = 9 × 10⁵ × 2.5/1.0

= 22.5 × 10⁵ N m-2

glad help you

it helps you

thank you

Answer 2

Answer:

the right answer is 6×10 to the power 5

Explanation:since it is given,

volume 1 = 2.5L

and, pressure 1= 9×10 to the power 5 n/m²

volume 2= 1.5L

pressure 2= ?

since we know p1.v1=p2.v2

2.5×9×1000000= p2×1.5

p2=  2.5×1000000/1.5

p2=  15×10000000n/m²

since we have to find additional pressure required to decrease the volume of gas to 1.5L

so subtract final pressure- initial pressure

i.e;  p2- p1

15×10000000- 9×1000000= 6×1000000n/m²