Question

A gas tank hold 2785a gas tank hold 2785 of propane 830 mm hg .What is the volume of the propane and standard volume?​

Answer 1

Problem:

A gas tank holds 2785L of propane ,C3H8, at 830. mm Hg. What is the volume of propane at standard pressure?

Note:

At STP (standard temperature and pressure), pressure is 1 atm which is equal to 760 mmHg.

Given Data:

V₁ (initial volume) = 2785 L            

V₂ (final volume) = ? unknown

P₁(initial pressure) = 830 mmHg     

P₂ (final pressure) = 1 atm or 760 mmHg

Solution:

This problem can be solve using Boyle's Law in which volume is inversely proportional to pressure when temperature and the amount of gas are constant. When pressure decreases, volume increases.

The formula of Boyle's Law is   P1V1 = P2V2

To find V₂, we can use V₂ = P₁V₁ / P₂

P₂ = P₁V₁ / V₂

= 830 mmHg  × 2785 L / 760 mmHg   (cancel unit mmHg)

    = 2,311,550 L / 760

    = 3041.51 L

Answer:

• Final volume is 3041.51 L