a gas under pressure of 2 bar occupies a volume of 100L at 20C. what temperature will the gas have when it is placed in an evacuated chamber of volume 175L? the pressure of the gas in the chamber is on-third of the initial pressure.
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Combined Gas Law :
(P1V1)/T1 =(P2V2)/T2
(2*100)/20 =(2/3*175)/T2
T2 = 11.667 oC
(P1V1)/T1 =(P2V2)/T2
(2*100)/20 =(2/3*175)/T2
T2 = 11.667 oC
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