Question

a gas which occupies a volume of one-fifth of the air

Answer 1

Answer:

I fond: 1029.7ml

Explanation:

Considering the gas as ideal we can use:
PV=nRT
Where:
P= pressure;
V= volume;
n= number of moles;
R= universal gas constant;
T= temperature.
So pasically our gas undergo a transformation from equilibrium state 1 to equilibrium state 2 where we have:
from:
P1V1=nRT1
to:
P2V2=nRT2

But n and P remain unchanged so we have that:
V1T1=nRP1
V2T2=nRP1
and so:
V1T1=V2T2

But:
T1=273+25=298K
T2=273+50=323K
and:
V2=950⋅323298=1029.7ml

Answer 2

Oxygen is nearly one-fifth (21%)