Question

) A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapour density is 29 , find its molecularformula.( C=12 ,H=1)

Answer 1

Answer:

% of carbon = 82.76

% of hydrogen = 17.24

Empirical Formula = C2H5

Empirical formula weight = 29

Vapour Density = 29

Relative molecular mass = 29 *2 = 58

n = Relative molecular mass / Empirical weight

n = 2

Molecular Formula = n* empirical formula = C4H10