Question

a gaseous mixture contain equal mass of O2 and SO2 . the mole fraction of SO2 in the mixture is??​

Answer 1

Answer ⇒ The mole fraction of SO₂ is 1/3.

Explanation ⇒ Let the mass of the sulphur dioxide and Oxygen be m grams.

Molar mass of Oxygen = 32 g/mole.

Molar mass of Sulphur dioxide = 64 g/mole.  

∴ moles of Oxygen = m/32

moles of Sulphur dioxide = m/64

Now, Mole Fraction of Sulphur dioxide = moles of SO₂/(M=moles of SO₂ + moles of O₂)

= (m/64)/(m/64 + m/32)

= (1/64)/(3/64)

= 1/3

Hence, the mole fraction of SO₂ is 1/3.

Hope it helps.

Answer 2

Answer:

GIVEN ANSWER IS TO FIND MOLE FRACTION OF SO2=?

Explanation:

I HAVE FOUND THE MOLE FRACTION OF O2 IN PLACE OF O2 SUBSTITUTE SO2