Question

A gaseous mixture contains 56g nitrogen 44g carbon dioxide and 16g methane the total pressure of mixture is 720mm what is the partial pressure of methane

Answer 1

See bro,the answer is 180mm.

Thanks.
Tripathy.

Answer 2

Answer: 180 mm Hg

Explanation: Partial pressure is calculated by multiplying the mole fraction by the total pressure.

$p_i=x_i\times P_{total}$

p= partial pressure

x = mole fraction=\frac{\text {moles of that substance}}{\text {Total moles}}[/tex]

Moles is calculated by using the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

${\text {Moles of} N_2}=\frac{56g}{28g/mol}=2mole$

${\text {Moles of} CO_2}=\frac{44g}{44g/mol}=1mole$

${\text {Moles of} CH_4}=\frac{16g}{16g/mol}=1mole$

Total moles = 2+1+1=4

Mole fraction of methane=[/tex]\frac{1}{4}=0.25[/tex]

$p_{methane}=0.25\times 720mmHg=180mmHg$