A gaseous mixture contains 56g of n2,44g co2 and 16 g of ch4.total pressure is 720mm of hg then find partial pressure of cg4
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Mole of n2 = 56/28= 2
Mole of co2=44/44 =1
Mole of ch4= 16/16=1
Partial pressure of n2 = 2/4 ✖ 720 =360
Partial pressure of co2 =1 /4 ✖ 720 =180
Partial pressure of ch4= 1/4 ✖ 720 = 180
Mole of co2=44/44 =1
Mole of ch4= 16/16=1
Partial pressure of n2 = 2/4 ✖ 720 =360
Partial pressure of co2 =1 /4 ✖ 720 =180
Partial pressure of ch4= 1/4 ✖ 720 = 180
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