Question

a gaseous mixture contains Oxygen and Sulphur dioxide in the ratio of 1:4 by mass. Therefore, the ratio of their respective numbers of molecules is????

Answer 1

Answer: The ratio of their respective numbers of molecules is 1:2.

Explanation:

Ratio of $O_2 \&SO_2$ = 1:4

Let the mass of $O_2$ be 1x and mass of $SO_2$ be 4x.

Moles of $O_2=\frac{\text{mass of }O_2}{\text{molar mass}O_2}=\frac{1x}{32 g/mol}$

Moles of $SO_2=\frac{\text{mass of }SO_2}{\text{molar mass}sO_2}=\frac{4x}{64 g/mol}$

$\frac{\text{number of molecules of}O_2}{\text{number of molecules of}SO_2}$

$=\frac{\frac{1x\times N_A}{32 g/mol}}{\frac{4x\times N_A}{64 g/mol}}=\frac{1}{2}$

The ratio of their respective numbers of molecules is 1:2.

Answer 2

Answer :-

→ 1 : 2.

Step-by-step explanation :-

Let the ratio be x.

Therefore, mass of $O_2$ is 1x and mass of $SO_2$ is 4x.

Moles of $O_2 = \sf \frac{mass \: of O_2}{molar \: mass O_2}=\frac{1x}{32 g/mol}$

Moles of $SO_2= \sf \frac{ mass \: of SO_2}{molar \: masss O_2}=\frac{4x}{64 g/mol}$

$\it \because \frac{number \: of \: molecules \: of O_2}{number \: of \: molecules \: of SO_2}$

$\it =\frac{\frac{1x\times N_A}{32 g/mol}}{\frac{4x\times N_A}{64 g/mol}}=\frac{1}{2}$

The ratio of their respective numbers of molecules is 1:2.

Hence, it is solved.