a gaseous mixture has 2 moles of N2 and 1mole of He .the fraction of heat given to it at constant pressure,utilized for raise in internal energy is
1)6/19 2)13/19
3)1/3 4)2/3
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Answered by
1
Answer:
ANSWER
The internal energy of n moles of a gas is u=21nFRT
where F= number of degrees of freedom.
The internal energy of 2 moles of oxygen at temperature T is
u1=21×2×5RT=5RT(F=5 for oxygen molecule)
Total internal energy of 4 moles of argon at temperature T is
=u2=21×4×3RT=6RT
Total internal energy =u1+u2=11 RT.
Answered by
1
Answer:
Formula for C
V
for a mixture is:
n
T
C
VT
=n
1
C
V1
+n
2
C
V2
C
VT
=
2
2
5R
+
2
3R
=2R
C
PT
=C
VT
+R=3R
Thus, ratio =1.5
Explanation:
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