Question

a gaseous mixture of A,B and C has a pressure of 10 atm.The total no. of moles of all gases is 10.The partial pressure of A and B are 3 and 1 atm respectively. If C has a molecular weight of 2,what is the weight of C in grams present in the mixture?

Answer 1

Answer:

6moles of c=12 g of c gas

Explanation:

Ok

Total pressure=10.

Partial pressure of a+partial pressure of b+partial pressure of c=10

Then Partial pressure of c =6 atm

Partial pressure of c =

moles of c x total pressure/ total moles

After calculation moles of c =6

And

moles of c x molecular mass of c= weight of c

So weight =12 g

Answer 2

Answer:

12 g

Explanation:

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