Question

A gaseous mixture of H2 and CO2 gas contains 66% by mass of CO2. find the vapour density of the mixture

Answer 1

Given:
Let total moles of mixture be 100g
Moles of CO2 = 66g
Then hydrogen will be = 34g
Number of moles of CO2=66/44=1.5
Numbsr of moles if H2=34/2=17
Total moles =1.5+17=18.5
Formula to be used:
Mavg= Total mass/ total moles
= 100/18.5=5.40
VAPOUR DENSITY= MAvg/2
=5.40/2=2.70
So, VAPOUR density of mixture is 2.7

Answer 2

Answer:2.7

Explanation:formula of vapour density =average mass(Mavg.) /2

M avg. =total mass /total mole

Let mass of mixture be 100g

So mass of co2=66g

Mass of h2=34g

mole of co2=1.5

Mole of h2=17

Total mole=18.5

M avg. =100/18.5

=5.4

Vapour density =5.4/2

=2.7