Question

A gaseous mixture of propane and methane in a vessel
exerts a pressure of 260 mm Hg at certain temperature
T. The mixture is burnt in excess O2 and all the carbon
is recovered as CO2. At the same temperature, the
produced CO2 exerts 572 mm Hg pressure in the same
vessel. The mass ratio of propane to methane in the
original mixture is​

Answer 1

Answer:

ANSWER

                                    C3H8+5O2⟶3CO2+4H2O

Let moles of C3H8 be x                            3x

                                    CH4+2O2⟶CO2+2H2O

Let moles of CH4 be  y                              y

Before reaction, mixture contained C3H8 and CH4

Total moles =x+y

P=320 mmHg

From ideal gas equation is  PV=nRT

⟹320×V=(x+y)RT (equation 01)

Pressure exerted by recovered CO2=448 mmHg

Total moles of CO2=(3x+y)

∴ Using PV=nRT

⟹448×V=(3x+y)RT (equation 2)

equation 01 is divided by 02

448V320V=(3x+

Explanation:

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