Question

a gases mixture containing 2g H2, 8g He, 22g co2 , and 8g o2 is enclosed in a vessel the gas with highest partial pressure is

Answer 1

Hii Dear,

◆ Answer -

He gas

◆ Explanation -

# Given -

W(H2) = 2 g

W(He) = 8 g

W(CO2) = 22 g

W(O2) = 8 g

# Solution -

Moles of H2 are calculated by -

n(H2) = W(H2)/M(H2)

n(H2) = 2/2

n(H2) = 1 mol

Moles of He are calculated by -

n(He) = W(He)/M(He)

n(He) = 8/4

n(He) = 2 mol

Moles of CO2 are calculated by -

n(CO2) = W(CO2)/M(CO2)

n(CO2) = 22/44

n(CO2) = 0.5 mol

Moles of O2 are calculated by -

n(O2) = W(O2)/M(O2)

n(O2) = 8/32

n(O2) = 0.25 mol

Partial pressure of the gas is directly proportional to mole fraction of gas. Hence, gas having maximum moles in mixture will have highest partial pressure.

Therefore, He gas will have max partial pressure.

Thanks dear..

Answer 2

Answer:

A gaseous mixture containing 2g H2, 8g He, 22g CO2, and 8g O2 is enclosed in a vessel. The gas with highest partial pressure is helium because it has the maximum number of moles i.e. 2

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