Question

A gene locus has 2 alleles A,a lf the frequency of dominant allele A is 0.4 then what will be the frequency of homozygous dominant heterozugous and homozygous recessive individuals in the population​

Answer 1

$\huge{ Answer -}$

● Frequency of homozygous dominant is A^2 = (0.4)^2 = 0.16

● We know that,

• A + a = 1
• 0.4 + a = 1
• a = 1 - 0.4
• a = 0.6

●So, frequency of homozygous recessive allele = (0.6)^2 = 0.36

●Frequency of heterozygous allele = 2Aa

=> 2 × 0.4 × 0.6

=> 0.48

Answer 2

Answer:

● Frequency of homozygous dominant is A^2 = (0.4)^2 = 0.16

● We know that,

A + a = 1

0.4 + a = 1

a = 1 - 0.4

a = 0.6

●So, frequency of homozygous recessive allele = (0.6)^2 = 0.36

●Frequency of heterozygous allele = 2Aa

=> 2 × 0.4 × 0.6

=> 0.48