Question

A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency
of homozygous dominant, heterozygous and homozygous recessive individuals in the population?

Answer 1

Frequency of dominant allele (say p) = 0.4

Frequency of recessive allele (say q)

= 1 – 0.4 = 0.6

 Frequency of homozygous dominant individuals (AA)

= p2 = (0.4)2 = 0.16

Frequency of heterozygous individuals (Aa)

= 2pq = 2(0.4)(0.6) = 0.48

Frequency of homozygous recessive individuals (aa)

= q2 = (0.6)2 = 0.36

Answer 2

GIVEN:

Frequency of dominant allele (p) = 0.4

SOLUTION:

Frequency of recessive allele(q)=1-0.4=0.6

frequency of homozygous dominant (AA)

=p²=0.16

frequency of homozygous recessive(aa)

=q²=0.36

frequency of heterozygous individuals (pq)

=2pq=2×0.6×0.4=0.48

I hope this helps ( ╹▽╹ )