Physics, asked by rsamu8209, 1 month ago

A general graph Showing Variation in potential energy (PE) of a particle with time while executing S. H. M. is​

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Answered by A1111
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PE \: of \: SHM \:  =  \frac{1}{2} m\omega^{2} x^{2}  \\ =  \frac{1}{2} m \omega^{2} A^{2} sin^{2}( \omega\:t  +  \phi)

So, option 2 is correct.

Hope, this helps...

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