Question

a general having lost 2/13 of his soldiers in a battle and 20%of the remainder by sickness,has 4400 left .how many soldiers had he at first ?​

Answer 1

Answer: 6500

Step-by-step explanation:

Let the initial strength of soldiers be 'x'. Now, 2/13 of the initial number of soldiers were lost in battle. Thus, number of soldiers now left

=$x-\frac{2}{13} x$

20% of this remaining strength were further lost due to sickness. Therefore, number of soldiers finally remaining is

$(x-\frac{2}{13} x)-\frac{20}{100} (x-\frac{2}{13}x)=4400(given)$

Solving this equation finally yields

x=6500

Answer 2

Answer:

Soldiers lost=2/13

Remaining=11/13

Sickness 11/13x20/100 = 11/65

Total: 2/13 +11/65=21/65

Remaining=44/65

Soldiers at first =44oox 65/44 =

65oo. Ans