Question

A generator has a probability of 0.80 to operate successfully, while that of the welding machine is 0.75. What is the likelihood that only the welding machine operates successfully?

Answer 1

The generator has a 20% chance not to work, and the welding machine has a 75% chance of working.

Multiplying 0.20*0.75=0.15, or 15% chance.

I'm not very good with probability, I apologize if I took the wrong approach to the problem.

Answer 2

Concept:

The language of sets is used in probability theory. Probability is defined and computed for sets, as we will see later. A set is a group of related things. The things in a set can be in any order, and the order of the objects inside them has no bearing.

Given:

Probability of generator $P(A)=0.8$.

Probability of welding machine $P(B)=0.75$.

Find:

The probability of operating only welding machine successfully.

Solution:

Probability of generator $P(A)=0.8$.

Probability of welding machine $P(B)=0.75$.

$P(A \cup B) = 1\\P(A \cup B) = P(A)+P(B)-P(A \cap B)\\1 = 0.8+0.75-P(A \cap B)\\\\P(A \cap B) = 0.55$

The probability of operating only welding machine is $= P(B)-P(A \cap B)$

                                                                                         $= 0.75-0.55$

                                                                                         $= 0.2$

Hence, the probability of operating only welding machine successfully is $0.2$.