A geostationary satellite is moving in a circular orbit at a height of 36000 km from the surface of
earth. Calculate its speed if it takes 24 hours to revolve around the earth ? (Given radius of earth
6400 km)
Answers
Answered by
0
Answer:
The radius of the orbit =6400+36000=42400km
circumference of the orbit 2πR
=2×3.14×42400
=266272km
speed= distance/time
= 24/266272 =11094.67km/h.
Answered by
0
Answer:
11094.67
Explanation:
The radius of the orbit= 6400+36000= 42400km
circumference of the orbit 2πr
2*3.14*42400
266272
speed= distance/time
266272/24 = 11094.67 km/h
Similar questions