A get 30% of the maximum mark and gey failed by 25 mark whereas B get 40% of the total marks in the same exam and get 25% of the passing marks more than the passing marks. find the passing marks of the exam.
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I hope it help you.
Step-by-step explanation:
A student got 30% marks and failed by 25 marks.
⟹minimum passing marks=30%+25
Another student got 40% marks which is 25% more than the minimum passing marks.
⟹125100(30%+25)=40%
⟹5(30%+25)=160%
⟹150%+125=160%
⟹125=10%
Now you know the percentage value of something, so you can easily calculate the maximum value (100%) of that.
Multiply with 10 on both sides.
Hence, the maximum marks of the test were simply1250
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