A giant squid of length 20.0m is vertical in seawater, with the top of the squid at a depth of 8.00m. The density of seawater is 1050kgm–3. What is the difference in pressure between the top and the bottom of the squid?
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P= hρg
P = (20+8) x 1050 x 9.8
P = 28 x 1050 x 8
P = 288120 Pa = 2.88 x 10⁵ = 2.88 atm ≈ 2.9 atm
P = (20+8) x 1050 x 9.8
P = 28 x 1050 x 8
P = 288120 Pa = 2.88 x 10⁵ = 2.88 atm ≈ 2.9 atm
farhanadbip59a8n:
it should be 20-8... and after that find out pressure above and pressure below and add up both ... answer is 206000 pa .. This is an AS level question so i know
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1
P= hρg h= height, g=acceleration due to gravity. P= pressure. Pa is the unit of pascal.
P = (20-8) x 1050 x 9.8
P = 12 x 1050 x 8
P = 100800 Pa
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