Physics, asked by naazia555, 1 year ago

A giant squid of length 20.0m is vertical in seawater, with the top of the squid at a depth of 8.00m. The density of seawater is 1050kgm–3. What is the difference in pressure between the top and the bottom of the squid?

Answers

Answered by TheEdward
5
P= hρg 

P = (20+8) x 1050 x 9.8 

P = 28 x 1050 x 8 

P = 288120 Pa = 2.88 x 10⁵ = 2.88 atm ≈ 2.9 atm 


farhanadbip59a8n: it should be 20-8... and after that find out pressure above and pressure below and add up both ... answer is 206000 pa .. This is an AS level question so i know
Answered by franktheruler
1

P= hρg h= height, g=acceleration due to gravity. P= pressure. Pa is the unit of pascal.


P = (20-8) x 1050 x 9.8


P = 12 x 1050 x 8


P = 100800 Pa

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